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翻訳と辞書　辞書検索 [ 開発暫定版 ] スポンサード リンク squeeze operator ： ウィキペディア英語版 squeeze operator In quantum physics, the squeeze operator for a single mode of the electromagnetic field is :$\backslash hat(z)\; =\; \backslash exp\; \backslash left\; (\; (z^$ * \hat^2 - z \hat^) \right ) , \qquad z = r e^ where the operators inside the exponential are the ladder operators. It is a unitary operator and therefore obeys $S(\backslash zeta)S^\backslash dagger\; (\backslash zeta)=S^\backslash dagger\; (\backslash zeta)S(\backslash zeta)=\backslash hat\; 1$, where $\backslash hat\; 1$ is the identity operator. Its action on the annihilation and creation operators produces :$\backslash hat^(z)\backslash hat\backslash hat(z)=\backslash hat\backslash cosh\; r\; -\; e^\; \backslash hat^\; \backslash sinh\; r\; \backslash qquad\backslash text\backslash qquad\; \backslash hat^(z)\backslash hat^\backslash hat(z)=\backslash hat^\backslash cosh\; r\; -\; e^\; \backslash hat\; \backslash sinh\; r$ The squeeze operator is ubiquitous in quantum optics and can operate on any state. For example, when acting upon the vacuum, the squeezing operator produces the squeezed vacuum state. The squeezing operator can also act on coherent states and produce squeezed coherent states. The squeezing operator does not commute with the displacement operator: : $\backslash hat(z)\; \backslash hat(\backslash alpha)\; \backslash neq\; \backslash hat(\backslash alpha)\; \backslash hat(z),$ nor does it commute with the ladder operators, so one must pay close attention to how the operators are used. Application of both operators above on the vacuum produces squeezed states: :$\backslash hat(\backslash alpha)\backslash hat(r)|0\backslash rangle=|\backslash alpha,r\backslash rangle$. ==See also== * Squeezed coherent state 抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』 ■ウィキペディアで「squeeze operator」の詳細全文を読む スポンサード リンク 翻訳と辞書 : 翻訳のためのインターネットリソース Copyright(C) kotoba.ne.jp 1997-2016. All Rights Reserved.